12x^2+60x=-48

Solution for 12x^2+60x=-48 equation:

12x^2+60x=-48

We move all terms to the left:

12x^2+60x-(-48)=0

We add all the numbers together, and all the variables

12x^2+60x+48=0

a = 12; b = 60; c = +48;
Δ = b2-4ac
Δ = 602-4·12·48
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-36}{2*12}=\frac{-96}{24}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+36}{2*12}=\frac{-24}{24}
=-1
$